grepでファイルからシャープ(#)とセミコロン(;)と空白行を除いたものを取り出す

コメント(#や;)と空白を除いて出力したい場合があります。

$ grep -v -e '^;' -e '^#' -e '^\s*$' /etc/samba/smb.conf 
[global]
   workgroup = WORKGROUP
	server string = %h server (Samba, Ubuntu)
   dns proxy = no
   log file = /var/log/samba/log.%m
   max log size = 1000
   syslog = 0
   panic action = /usr/share/samba/panic-action %d
   server role = standalone server
   passdb backend = tdbsam
   obey pam restrictions = yes
   unix password sync = yes
   passwd program = /usr/bin/passwd %u
   passwd chat = *Enter\snew\s*\spassword:* %n\n *Retype\snew\s*\spassword:* %n\n *password\supdated\ssuccessfully* .
   pam password change = yes
   map to guest = bad user
   usershare allow guests = yes
[printers]
   comment = All Printers
   browseable = no
   path = /var/spool/samba
   printable = yes
   guest ok = no
   read only = yes
   create mask = 0700
[print$]
   comment = Printer Drivers
   path = /var/lib/samba/printers
   browseable = yes
   read only = yes
   guest ok = no

こんな感じで↑いけます。

– 「’^;’」はセミコロンの行にマッチ
– 「’^#’」はシャープの行にマッチ
– 「’^\s*$’」は空白行にマッチ

です。

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